Problem 3:

A circular coil of wire (radius = 0.5 m, 12 turns) is located in the xy plane. The total resistance of the coil is 5 . The coil is at first situated in a constant magnetic field B = (0.5i + 0.7k) Tesla.
  1. Find the magnitude of the magnetic flux through the coil.
  2. Now suppose the magnetic field is time-dependent (t=time) and is given by B = (1-0.4 t) k in units of Tesla. What is the magnitude of the current in the coil at time t=5 s?
Solution:

  1. The magnetic flux is given by

       øB = N B · ñ dA

    If the coil is in the x-y plane, then the normal to the surface ñ is in the k or -k direction. Thus the dot product is easy ->
    B · ñ = (0.5i + 0.7k) · k = 0.7 T (we are only concerned with the magnitude of the flux, so we don't need to worry about the possible minus sign). This is constant over the area of the coil, so the integral is just the total area = (0.5 m)2 and the total flux is

       øB = (12)(0.7 T)( (0.5 m)2) = 6.60 Wb

  2. This requires Faraday's law. The changing magnetic flux will induce an EMF which will cause a current in the coil. We have

      E = - døB/dt = - d/dt [1-0.4t](N r2) = 0.4 N r2 = 0.4 (12) ( (0.5 m)2) = 3.77 V

    Using V = IR, the current in the coil will be

       I = E/R = 3.77V/5 = 0.754 A.


Problem 4
Test 3
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last updated: April 26 1998